A^2=40+13a

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Solution for A^2=40+13a equation: 



^2=40+13A

We move all terms to the left:

^2-(40+13A)=0

We add all the numbers together, and all the variables

-(13A+40)+^2=0

We add all the numbers together, and all the variables

-(13A+40)=0

We get rid of parentheses

-13A-40=0

We move all terms containing A to the left, all other terms to the right

-13A=40

A=40/-13

A=-3+1/13

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